Let $q$ be a scalar that is not a root of unity. We show that any
nonzero polynomial in the Casimir element of the Fairlie-Odesskii
algebra $U_q'(\mathfrak{so}_3)$ cannot be expressed in terms of
only Lie algebra operations performed on the generators
$I_1,I_2,I_3$ in the usual presentation of
$U_q'(\mathfrak{so}_3)$. Hence, the vector space sum of the center
of $U_q'(\mathfrak{so}_3)$ and the Lie subalgebra of
$U_q'(\mathfrak{so}_3)$ generated by $I_1,I_2,I_3$ is direct.
Lie polynomial Casimir element quantum group quantum algebra
Birincil Dil | İngilizce |
---|---|
Konular | Matematik |
Bölüm | Makaleler |
Yazarlar | |
Yayımlanma Tarihi | 17 Temmuz 2021 |
Yayımlandığı Sayı | Yıl 2021 |