This paper shows the solution form of the rational difference equation \begin{equation*} x_{n+1}=\frac{ax_{n-(2k+3)}}{-a\mp x_{n-(k+1)}x_{n-(2k+3)}}\text{ }% ,~n=0,1,... \end{equation*} where $k$ is a positive integer $a$ and initial conditions are non-zero real numbers with $x_{n-(k+1)}x_{n-(2k+3)}\neq \mp a$ for all $n\in N_{0}$.
Primary Language | English |
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Subjects | Mathematical Sciences |
Journal Section | Articles |
Authors | |
Publication Date | April 30, 2023 |
Submission Date | October 22, 2022 |
Acceptance Date | April 28, 2023 |
Published in Issue | Year 2023 Volume: 11 Issue: 1 |