On the Exponential Diophantine Equation $(6m^{2}+1)^{x}+(3m^{2}-1)^{y}=(3m)^{z}$
Abstract
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References
- [1] L. Jesmanowicz, Some remarks on Pythagorean numbers, Wiadom Mat 1, (1955/1956), 196-202.
- [2] N. Terai, The Diophantine equation $a^x+b^y=c^z$, Proc. Japan Acad. Ser. A Math. Sci., 70 (1994), 22-26.
- [3] M. Le, R. Scott, R. Styer, A survey on the ternary purely exponential Diophantine equation $a^x + b^y = c^z$, Surv. Math. Appl., 214 (2019), 109-140.
- [4] M. Alan, On the exponential Diophantine equation $ (m^2+m+1)^x+m^y=(m+1)^z$, Mediterr. J. Math., 17 (189) (2020), 1-8.
- [5] M. Alan, On the exponential Diophantine equation $ m^x+(m+1)^y=(1+m+m^2)^z$, An. St. Univ. Ovidius Constanta, Ser. Mat., 29 (3) (2021), 23-32.
- [6] Z. Cao, A note on the Diophantine equation $a^x+ b^y = c^z$, Acta Arith., 91 (1999), 85-93.
- [7] E. Kızıldere, M. Le, G. Soydan, A note on the ternary purely exponential Diophantine equation $A^x + B^y = C^z$ with $A + B = C^2$, Stud. Sci. Math. Hung., 57 (2) (2020), 200-206.
- [8] T. Miyazaki, Exceptional cases of Terai's conjecture on Diophantine equations, Arch. Math., 95 (2010), 519-527.
Details
Primary Language
English
Subjects
Mathematical Sciences
Journal Section
Research Article
Publication Date
September 23, 2022
Submission Date
December 20, 2021
Acceptance Date
June 29, 2022
Published in Issue
Year 2022 Volume: 5 Number: 3
Cited By
On the Diophantine Equation $\left(9d^2 + 1\right)^x + \left(16d^2 - 1\right)^y = (5d)^z$ Regarding Terai's Conjecture
Journal of New Theory
https://doi.org/10.53570/jnt.1479551On the Diophantine Equation $(8r^2+1)^x+(r^2-1)^y=(3r)^z$ Regarding Terai's Conjecture
Communications in Advanced Mathematical Sciences
https://doi.org/10.33434/cams.1561789
