In this paper construction of normalizer of Dn in V (ZDn) is reduced to construction of integral group ring of its cyclic subgroup. In a better expression, we have shown that NU (Dn) = Dn × F, where F is a free abelian group with rank ρ = 1 2 ϕ(n) − 1.
Other ID | JA54JP54YC |
---|---|
Journal Section | Articles |
Authors | |
Publication Date | June 1, 2008 |
Published in Issue | Year 2008 Volume: 3 Issue: 3 |