In this paper construction of normalizer of Dn in V (ZDn) is reduced to construction of integral group ring of its cyclic subgroup. In a better expression, we have shown that NU (Dn) = Dn × F, where F is a free abelian group with rank ρ = 1 2 ϕ(n) − 1.
Diğer ID | JA54JP54YC |
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Bölüm | Makaleler |
Yazarlar | |
Yayımlanma Tarihi | 1 Haziran 2008 |
Yayımlandığı Sayı | Yıl 2008 Cilt: 3 Sayı: 3 |