Let $G$ be a finite non-solvable group. In this paper, we show that if $1/8$ of elements of $G$ have order two, then $G$ is either a simple group
isomorphic to $PSL_{2}(q)$, where $q\in\{7,8,9\}$ or $G\cong GL_{2}(4).\mathbb{Z}_2 In fact
in this paper, we answer Problem 132 in [1].
| Primary Language | English |
|---|---|
| Subjects | Mathematical Sciences |
| Journal Section | Research Article |
| Authors | |
| Publication Date | February 1, 2015 |
| Published in Issue | Year 2015 Volume: 44 Issue: 1 |