Let $R$ be a ring which is not commutative. Assume that either $R$ is alternative, but not associative, or $R$ is associative and any commutator $v\in R$ satisfies: $v^2$ is in the center of $R.$ We show (using commutators) that if $R$ contains no divisors of zero and $\text{char}(R)\ne 2,$ then $R//C,$ the localization of $R$ at its center $C,$ is the octonions in the first case and the quaternions, in latter case. Our proof in both cases is essentially the same and it is elementary and rather self contained. We also give a short (uniform) proof that if a non-zero commutator in $R$ is not a zero divisor (with mild additional hypothesis when $R$ is alternative, but not associative (e.g.~that $(R,+)$ contains no $3$-torsion), then $R$ contains no divisors of zero.
Primary Language | English |
---|---|
Subjects | Algebra and Number Theory |
Journal Section | Articles |
Authors | |
Early Pub Date | April 19, 2024 |
Publication Date | July 12, 2024 |
Submission Date | February 1, 2024 |
Acceptance Date | April 8, 2024 |
Published in Issue | Year 2024 Volume: 36 Issue: 36 |