Let (M_k) be the sequence of Mulatu numbers defined by M_0=4, M_1=1, M_k=M_(k-1)+M_(k-2) and (F_k) be the Fibonacci sequence given by the recurrence F_k=F_(k-1)+F_(k-2) with the initial conditions F_0=0, F_1=1 for k≥2. In this paper, we showed that all Mulatu numbers, that are concatenations of two Fibonacci numbers are 11,28. That is, we solved the equation M_k=〖10〗^d F_m+F_n, where d indicates the number of digits of F_n. We found the solutions of this equation as (k,m,n,d)∈{(4,2,2,1),(6,3,6,1)}. Moreover the solutions of this equation displayed as M_4=(F_2 F_2 ) ̅=11 and M_6=(F_3 F_6 ) ̅=28. Here the main tools are linear forms in logarithms and Baker Davenport basis reduction method.
Mulatu and Fibonacci numbers, linear forms in logarithms, exponential Diophantine equations
Linear forms in logarithms, Mulatu and Fibonacci numbers, reduction method, exponantial Diophantine equations
Primary Language | English |
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Subjects | Mathematical Sciences |
Journal Section | Research Articles |
Authors |
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Early Pub Date | October 5, 2023 |
Publication Date | October 18, 2023 |
Submission Date | January 16, 2023 |
Acceptance Date | June 8, 2023 |
Published in Issue | Year 2023 Volume: 27 Issue: 5 |
Sakarya University Journal of Science (SAUJS)