The 3-GDDs of type $g^3u^2$

Öz

A 3-GDD of type ${g^3u^2}$ exists if and only if  $g$ and $u$ have the same parity, $3$ divides $u$ and $u\leq 3g$.Such a 3-GDD of type ${g^3u^2}$ is  equivalent to an edge  decomposition of $K_{g,g,g,u,u}$ into triangles.

Kaynakça

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